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By Computing the Shortest Distance Determine Whether the Following Pairs of Lines Intersect Or Not: X − 5 4 = Y − 7 − 5 = Z + 3 − 5 a N D X − 8 7 = Y − 7 1 = Z − 5 3

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प्रश्न

By computing the shortest distance determine whether the following pairs of lines intersect or not: \[\frac{x - 5}{4} = \frac{y - 7}{- 5} = \frac{z + 3}{- 5} \text{ and } \frac{x - 8}{7} = \frac{y - 7}{1} = \frac{z - 5}{3}\]

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उत्तर

\[\frac{x - 5}{4} = \frac{y - 7}{- 5} = \frac{z + 3}{- 5} \text{ and } \frac{x - 8}{7} = \frac{y - 7}{1} = \frac{z - 5}{3}\]  Since the first line passes through the point (5, 7,-3)  and has direction ratios proportional to 4, -5,-5  its vector equation is 

\[\overrightarrow{r} = \overrightarrow{a_1} + \lambda \overrightarrow{b_1} . . . (1) \]

\[\text{ Here } , \]

\[ \overrightarrow{a_1} = 5 \hat{i}  + 7 \hat{j} - 3 \hat{k} \]

\[ \overrightarrow{b_1} = 4 \hat{i} - 5 \hat{j} - 5 \hat{k}\] 

Also, the second line passes through the point (8, 7, 5) and has direction ratios proportional to 7, 1, 3.
Its vector equation is

\[\overrightarrow{r} = \overrightarrow{a_2} + \mu \overrightarrow{b_2} . . . (2) \]

\[\text{ Here } , \]

\[ \overrightarrow{a_2} = 8 \hat{i} + 7 \hat{j} + 5 \hat{k} \]

\[ \overrightarrow{b_2} = 7 \hat{i} + \hat{j} + 3 \hat{k} \]

Now,

\[\overrightarrow{a_2} - \vec{a_1} = 3 \hat{i} + 8 \hat{k} \]

\[\text{ and  } \overrightarrow{b_1} \times \overrightarrow{b_2} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \\ 4 & - 5 & - 5 \\ 7 & 1 & 3\end{vmatrix}\]

\[ = - 10 \hat{i} - 47 \hat{j} + 39 \hat{k} \]

\[\left( \overrightarrow{a_2} - \overrightarrow{a_1} \right) . \left( \overrightarrow{b_1} \times \overrightarrow{b_2} \right) = \left( 3 \hat{i} + 8 \hat{k} \right) . \left( - 10 \hat{i} - 47 \hat{j} + 39 \hat{k} \right)\]

\[ = - 30 + 312\]

\[ = 282\]

\[\text{ We observe }\]

\[\left( \overrightarrow{a_2} - \overrightarrow{a_1} \right) . \left( \overrightarrow{b_1} \times \overrightarrow{b_2} \right) \neq 0\]

\[\text{ Thus, the given lines do not intersect } .\]

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अध्याय 27: Straight Line in Space - Exercise 28.5 [पृष्ठ ३८]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 27 Straight Line in Space
Exercise 28.5 | Q 3.4 | पृष्ठ ३८

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