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Find the Cartesian Equation of the Line Which Passes Through the Point (−2, 4, −5) and Parallel to the Line Given by X + 3 3 = Y − 4 5 = Z + 8 6 .

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प्रश्न

Find the cartesian equation of the line which passes through the point (−2, 4, −5) and parallel to the line given by  \[\frac{x + 3}{3} = \frac{y - 4}{5} = \frac{z + 8}{6} .\]

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उत्तर

We know that the cartesian equation of a line passing through a point with position vector \[\overrightarrow{a}\] and parallel to the vector \[\overrightarrow{b}\] is

\[\frac{x - x_1}{a} = \frac{y - y_2}{b} = \frac{z - z_3}{c}\] 

Here, 

\[\overrightarrow{a} = - 2 \hat{i} + 4j - 5 \hat{k} \]

\[ \overrightarrow{b} = 3 \hat{i} + 5 \hat{j} - 6 \hat{k} \]

The cartesian equation of the required line is 

\[\frac{x - \left( - 2 \right)}{3} = \frac{y - 4}{5} = \frac{z - \left( - 5 \right)}{6}\]

\[ = \frac{x + 2}{3} = \frac{y - 4}{5} = \frac{z + 5}{6}\]

\[\]

 

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अध्याय 27: Straight Line in Space - Exercise 28.2 [पृष्ठ १६]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 27 Straight Line in Space
Exercise 28.2 | Q 4 | पृष्ठ १६

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