Advertisements
Advertisements
प्रश्न
Briefly give the basis for Pauling's scale of electronegativity.
Advertisements
उत्तर
Pauling’s scale:
- Electronegativity is the relative tendency of an element present in a covalently bonded molecule to attract the shared pair of electrons towards itself.
- Pauling assigned arbitrary values of electronegativities for hydrogen and fluorine as 2.2 and 4, respectively.
- Based on this the electronegativity values for other elements can be calculated using the following expression.
(XA − XB) = `0.182 sqrt("E"_"AB" - ("E"_"AA" xx "E"_"BB")^(1/2))`
Where EAB, EAA, and EBB are the bond dissociation energies of AB, A2, and B2 molecules respectively.
XA and XB are electronegativity values of A and B.
APPEARS IN
संबंधित प्रश्न
Which of the following elements will have the highest electronegativity?
Which one of the following is true about metallic character when we move from left to right in a period and top to bottom in a group?
Is the definition given below for ionisation enthalpy is correct?
"Ionisation enthalpy is defined as the energy required to remove the most loosely bound electron from the valence shell of an atom"
Magnesium loses electrons successively to form Mg+, Mg2+ and Mg3+ ions. Which step will have the highest ionisation energy and why?
Energy of an electron in the ground state of the hydrogen atom is −2.18 × 10−18 J. Calculate the ionisation enthalpy of atomic hydrogen in terms of kJ mol−1.
Explain the Pauling method for the determination of ionic radius.
Why the first ionisation enthalpy of sodium is lower than that of magnesium while its second ionisation enthalpy is higher than that of magnesium?
By using Pauling's method calculate the ionic radii of K+ and Cl− ions in the potassium chloride crystal. Given that `"d"_("K"^+) - "Cl"^-` = 3.14 Å
Explain the following, give an appropriate reason.
Ionisation potential of N is greater than that of O
Explain the following, give an appropriate reason.
The formation of \[\ce{F^-_{(g)}}\] from \[\ce{F_{(g)}}\] is exothermic while that of \[\ce{O^2-_{(g)}}\] from \[\ce{O_{(g)}}\] is endothermic.
