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प्रश्न
Briefly explain various ways to increase the strength of the magnetic field produced by a given solenoid.
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उत्तर
The magnetic field inside a current-carrying solenoid is given by
B = μ0nI
where n is the number of turns per unit length in the solenoid, and I is the current through the wire.
As a result, increasing the current or the number of loops per metre would result in an increase in the magnetic field in the solenoid. Because the iron core is a magnet and is magnetised, it contributes flux to the solenoid's flux, hence increasing the magnetic field intensity.
The magnetic field strength produced by the solenoid can be raised by
- By inserting soft iron into the solenoid,
- By increasing the number of coil turns,
- By increasing the flow of electricity through the solenoid.
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संबंधित प्रश्न
Obtain an expression for magnetic induction along the axis of the toroid.
In Ampere's \[\oint \vec{B} \cdot d \vec{l} = \mu_0 i,\] the current outside the curve is not included on the right hand side. Does it mean that the magnetic field B calculated by using Ampere's law, gives the contribution of only the currents crossing the area bounded by the curve?
In order to have a current in a long wire, it should be connected to a battery or some such device. Can we obtain the magnetic due to a straight, long wire by using Ampere's law without mentioning this other part of the circuit?
A hollow tube is carrying an electric current along its length distributed uniformly over its surface. The magnetic field
(a) increases linearly from the axis to the surface
(b) is constant inside the tube
(c) is zero at the axis
(d) is zero just outside the tube.
In a coaxial, straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero
(a) outside the cable
(b) inside the inner conductor
(c) inside the outer conductor
(d) in between the tow conductors.
Consider the situation described in the previous problem. Suppose the current i enters the loop at the points A and leaves it at the point B. Find the magnetic field at the centre of the loop.
Ampere's circuital law is used to find out ______
A thick current carrying cable of radius ‘R’ carries current ‘I’ uniformly distributed across its cross-section. The variation of magnetic field B(r) due to the cable with the distance ‘r’ from the axis of the cable is represented by:
Two identical current carrying coaxial loops, carry current I in an opposite sense. A simple amperian loop passes through both of them once. Calling the loop as C ______.
- `oint B.dl = +- 2μ_0I`
- the value of `oint B.dl` is independent of sense of C.
- there may be a point on C where B and dl are perpendicular.
- B vanishes everywhere on C.
