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प्रश्न
Briefly explain various ways to increase the strength of the magnetic field produced by a given solenoid.
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उत्तर
The magnetic field inside a current-carrying solenoid is given by
B = μ0nI
where n is the number of turns per unit length in the solenoid, and I is the current through the wire.
As a result, increasing the current or the number of loops per metre would result in an increase in the magnetic field in the solenoid. Because the iron core is a magnet and is magnetised, it contributes flux to the solenoid's flux, hence increasing the magnetic field intensity.
The magnetic field strength produced by the solenoid can be raised by
- By inserting soft iron into the solenoid,
- By increasing the number of coil turns,
- By increasing the flow of electricity through the solenoid.
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संबंधित प्रश्न
State Ampere’s circuital law.
A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
In Ampere's \[\oint \vec{B} \cdot d \vec{l} = \mu_0 i,\] the current outside the curve is not included on the right hand side. Does it mean that the magnetic field B calculated by using Ampere's law, gives the contribution of only the currents crossing the area bounded by the curve?
A hollow tube is carrying an electric current along its length distributed uniformly over its surface. The magnetic field
(a) increases linearly from the axis to the surface
(b) is constant inside the tube
(c) is zero at the axis
(d) is zero just outside the tube.
A thin but long, hollow, cylindrical tube of radius r carries i along its length. Find the magnitude of the magnetic field at a distance r/2 from the surface (a) inside the tube (b) outside the tube.
Find the magnetic field due to a long straight conductor using Ampere’s circuital law.
Ampere’s circuital law is given by _______.
Read the following paragraph and answer the questions.
|
Consider the experimental set-up shown in the figure. This jumping ring experiment is an outstanding demonstration of some simple laws of Physics. A conducting non-magnetic ring is placed over the vertical core of a solenoid. When current is passed through the solenoid, the ring is thrown off. |
- Explain the reason for the jumping of the ring when the switch is closed in the circuit.
- What will happen if the terminals of the battery are reversed and the switch is closed? Explain.
- Explain the two laws that help us understand this phenomenon.
