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Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH3OH, CH3CN - Chemistry

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प्रश्न

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain.

Cyclohexane, KCl, CH3OH, CH3CN

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उत्तर

n-octane is a non-polar solvent. Therefore, the solubility of a non-polar solute is greater than that of a polar solute in n-octane.

The order of increasing polarity is:

Cyclohexane < CH3CN < CH3OH < KCl

Therefore, the order of increasing solubility is

KCl < CH3OH < CH3CN < Cyclohexane

The following explanation applies to this:

Since both cyclohexane and n-octane are non-polar, they are fully soluble in each other. Due to its ionic nature, KCl is the least soluble (nearly insoluble) in n-octane. Although CH3CN is less polar than CH3OH, both CH3CN and CH3OH are polar in nature. Therefore, CH3CN will be more soluble than CH3OH in the non-polar solvent n-octane.

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अध्याय 1: Solutions - Exercises [पृष्ठ २९]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 1 Solutions
Exercises | Q 1.24 | पृष्ठ २९

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