हिंदी

Assertion: The frequency of violet colour of wavelength 4000⁢Å is 7.5 × 10^14⁢ Hz. Reason: C =𝑣⁢𝜆 or 𝜈 = 𝑐𝜆 = 3 × 10^8/4000 × 10^−10 = 7.5 × 10^14 Hz

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प्रश्न

Assertion: The frequency of violet colour of wavelength \(4000 \AA\) is \(7.5 \times 10^{14} \mathrm{~Hz}\). 

Reason: \(\mathrm{C}=v \lambda\)

\[\text{or } \nu = \frac{c}{\lambda}\]

\[= \frac{3 \times 10^{8}}{4000 \times 10^{-10}}\]

= 7.5 × 1014 Hz

विकल्प

  • If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

  • If both Assertion and Reason are true, but Reason is not correct explanation of the Assertion.

  • If Assertion is true, but the Reason is false.

  • If Assertion is false, but the Reason is true.

MCQ
अभिकथन और तर्क
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उत्तर

If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

Explanation:

Using the wave formula $$c = \nu \lambda$$, the frequency is $$\nu = \frac{3 \times 10^8\text{ ms}^{-1}}{4000 \times 10^{-10}\text{ m}} = 7.5 \times 10^{14}\text{ Hz}$$.

Thus, the assertion is correct and directly justified by the reason.

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अध्याय 2: Light - Multiple Choice Questions and Assertion-Reason Type Questions [पृष्ठ १७३]

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फ्रैंक Physics Part 2 [English] Class 10 ICSE
अध्याय 2 Light
Multiple Choice Questions and Assertion-Reason Type Questions | Q 60. | पृष्ठ १७३
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