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Answer the following question: If A = [1ωω21], B = [ω211ω], where ω is a complex cube root of unity, then show that AB + BA + A −2B is a null matrix

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प्रश्न

Answer the following question:

If A = `[(1, omega),(omega^2, 1)]`, B = `[(omega^2, 1),(1, omega)]`, where ω is a complex cube root of unity, then show that AB + BA + A −2B is a null matrix

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उत्तर

ω is a complex cube root of unity

∴ ω3 = 1 and ω4 = ω3·ω = ω    ...(1)

Also 1 + ω + ω2 = 0   ...(2)

AB = `[(1, omega),(omega^2, 1)] [(omega^2, 1),(1, omega)]`

= `[(omega^2 + omega,1 + omega^2),(omega^4 + 1, omega^2 + omega)]`

BA = `[(omega^2, 1),(1, omega)] [(1, omega),(omega^2, 1)]`

= `[(omega^2 + omega^2, omega^3 + 1),(1 + omega^3, omega + omega)]`

= `[(2omega^2, 2),(2, 2omega)]` ...[∵ ω3 = 1]

∴ AB + BA + A – 2B

= `[(omega^2 + omega, 1 + omega^2),(omega^4 + 1, omega^2 + omega)] + [(2omega^2, 2),(2, 2omega)] + [(1, omega),(omega^2, 1)] -2[(omega^2, 1),(1, omega)]`

= `[(omega^2 + omega, 1 + omega^2),(omega^4 + 1, omega^2 + omega)] + [(2omega^2, 2),(2, 2omega)] + [(1, omega),(omega^2, 1)] - [(2omega^2, 2),(2, 2omega)]`

= `[(omega^2 + omega + 2omega^2 + 1 - 2omega^2, 1 + omega^2 + 2 + omega - 2),(omega^4 + 1 + 2 + omega^2 - 2,omega^2 + omega + 2omega + 1 - 2omega)]`

= `[(1 + omega + omega^2, 1 + omega + omega^2),(1 + omega + omega^2, 1 + omega + omega^2)]`  ...[∵ ω4 = ω]

= `[(0, 0),(0, 0)]`  ...[By (2)]

which is a null matrix.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Determinants and Matrices - Miscellaneous Exercise 4(B) [पृष्ठ १०१]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 4 Determinants and Matrices
Miscellaneous Exercise 4(B) | Q II. (11) | पृष्ठ १०१

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