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Find the value of a, b, c, and d from the equation: [a-b2a+c2a-b3x+d]=[-15013] - Mathematics

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प्रश्न

Find the value of a, b, c, and d from the equation:

`[(a-b, 2a+c),(2a-b, 3x+d)] = [(-1,5),(0,13)]`

योग
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उत्तर

`[(a-b, 2a+c),(2a-b, 3x+d)] = [(-1,5),(0,13)]`

As the two matrices are equal, their corresponding elements are also equal.

Comparing the corresponding elements, we get:

a − b = −1          ....(1)

2a − b = 0           ....(2)

2a + c = 5           ....(3)

3c + d = 13          ...(4)

From (2), we have:

b = 2a

Then, from (1), we have:

a − 2a = −1

⇒ a = 1

⇒ b = 2

Now, from (3), we have:

2 ×1 + c = 5

⇒ c = 3

From (4) we have:

3 ×3 + d = 13

⇒ 9 + d = 13

⇒ d = 4

∴ a = 1, b = 2, c = 3, and d = 4

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अध्याय 3: Matrices - Exercise 3.1 [पृष्ठ ६४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 3 Matrices
Exercise 3.1 | Q 7 | पृष्ठ ६४

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