हिंदी

Answer the following in brief. Calculate the number of atoms in fcc unit cell.

Advertisements
Advertisements

प्रश्न

Answer the following in brief.

Calculate the number of atoms in fcc unit cell.

टिप्पणी लिखिए
Advertisements

उत्तर

  1. A face-centred cubic (fcc) unit cell has particles at the eight corners plus particles at the centre of its six faces.
  2. Each particle present at the corner of a given unit cell is shared with seven other neighbouring unit cells. As a result, its contribution to the given unit cell is only `1/8`.
    Thus, the number of particles present at corners per unit cell
    = 8 corner atoms `xx 1/8` atom per unit cell = 1
  3. Each particle at the centre of the six faces is shared with one neighbouring cube. Thus, 1/2 of each face particle belongs to the given unit cell.
    Thus, the number of particles present at faces per unit cell
    = 6 atoms at the faces `xx 1/2` atom per unit cell = 3
    Therefore, fcc unit cell has one corner particle plus 3 face particles, making total of 4 particles per unit cell.
shaalaa.com
Cubic System
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Solid State - Exercises [पृष्ठ २६]

APPEARS IN

बालभारती Chemistry [English] Standard 12 Maharashtra State Board
अध्याय 1 Solid State
Exercises | Q 3.03 | पृष्ठ २६

संबंधित प्रश्न

Obtain the relationship between the density of a substance and the edge length of the unit cell.


Write the relationship between radius of atom and edge length of fcc unit cell.


Give the percentage of empty space in bcc lattice.


Calculate the number of unit cells in 0.3 g of a species having density of 8.5 g/cm3 and unit cell edge length 3.25 × 10-8 cm.


Silver crystallises in fcc structure, if edge length of unit cell is 316.5 pm. What is the radius of silver atom?


What is the percentage of unoccupied space in fcc unit cell?


An element (atomic mass M g/mol) having bcc structure has unit cell edge 400 pm. The density of the element is ____________ g/cm3.

[NA = 6.0 × 1023 atom mol−1)


How many total constituent particles are present in simple cubic unit cell?


The percentage of unoccupied volume in simple cubic cell is ______.


The number of atoms in 500 g of a fcc crystal of a metal with density d = 10 g/cm3 and cell edge 100 pm, is equal to ____________.


Consider the following unit cell.

The number of particles (spheres) per unit cell is:


A metallic element has a cubic lattice with edge length of unit cell 2 Å. Calculate the number of unit cells in 200 g of the metal, if density of metal is 2.5 g cm-3?


What is the density of iron crystal which crystallizes in body-centred cubic structure with edge length 287 pm? (At. mass of Fe = 56 amu)


The number of atoms in 100 g of an fcc crystal with density 10 g cm-3 and unit cell edge length 200 pm is equal to ______.


An element has a bee structure with unit cell edge length of 288 pm. How many unit cells and number of atoms are present in 200 g of the element?


In face centred cubic unit cell, what is the volume occupied?


Identify unit cell from following having four particles in it


What is the density of potassium, if it has a bcc structure with edge length 4Å?
(Atomic mass of K = 39)


At room temperature, polonium Crystallises in a primitive cubic unit cell. If a = 3.36 Å. Calculate the theoretical density of polonium. [It's atomic weight is 209 g/mol.]


Silver crystallizes in the fcc structure. If the edge length of the unit cell is 400 pm, calculate the density of silver (Atomic mass of Ag = 108).


The correct sequence of the atomic layers in cubic close packing is ______.


What would be the empirical formula of a compound having a unit cell containing A ion shared equally at the corner of the cube and B ion on the centre of faces of the cube?


The number of particles present in Face Centred Cubic Unit cell is/are ______.


The cubic unit cell of a metal (molar mass = 63.55g mol−1) has an edge length of 362 pm. Its density is 8.92g cm−3.

The type of unit cell is ______.


Calculate the molar mass of an element having density 2.8 g cm−3 and forms fcc unit cell.

[a3.NA = 38.5 cm3 mol−1]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×