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An Experimenter'S Diary Reads as Follows: "A Charged Particle is Projected in a Magnetic Field of ( 7.0 → I − 3.0 → J ) × 10 − 3 T. the Acceleration of the - Physics

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प्रश्न

An experimenter's diary reads as follows: "A charged particle is projected in a magnetic field of `(7.0 vec i - 3.0 vecj)xx 10^-3 `T. The acceleration of the particle is found to be `(x veci + 7.0 vecj )` The number to the left of i in the last expression was not readable. What can this number be?

योग
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उत्तर

Given,

Magnetic field, B = (7.0i − 3.0j) × 10−3 T

Acceleration of the particle, a = (xi + 7j) × 10−6 m/s2

We have denoted the unidentified number as x.

B and a are perpendicular to each other. (Because magnetic force always acts perpendicular to the motion of the particle)

So, the dot product of the two quantities should be zero.

That is, B.a = 0

⇒ 7x × 10−3 × 10−6 − 3 × 10−3 × 7 × 10−6 = 0

⇒ 7x − 21 = 0

`x = 21/7 = 3`

Acceleration of the particle is (3i + 7j) × 10−6 m/s2.

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Force on a Moving Charge in Uniform Magnetic and Electric Fields
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Magnetic Field - Exercises [पृष्ठ २३०]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 12 Magnetic Field
Exercises | Q 4 | पृष्ठ २३०

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