Advertisements
Advertisements
प्रश्न
An employee works in a company on a contract of 30 days on the condition that he will receive Rs. 120 for each day he works and he will be fined Rs. 10 for each day he is absent. If he receives Rs. 2300 in all, for how many days did he remain absent?
Advertisements
उत्तर
Given, total number of days in contract = 30
Money received per day for working = ₹ 120
Money deducted per day for being absent = ₹ 10
And amount received by employee as salary = ₹ 2300
Let the employee remained absent for x days.
Then, employee worked for (30 – x) days.
According to the question,
120(30 – x) – 10x = 2300
⇒ 3600 – 120x – 10x = 2300
⇒ – 130x = – 3600 + 2300
⇒ – 130x = – 1300
⇒ x = `-1300 xx ((-1)/130)`
∴ x = 10
Therefore, employee remained absent for 10 days.
APPEARS IN
संबंधित प्रश्न
The sum of three consecutive multiples of 8 is 888. Find the multiples.
I have a total of Rs 300 in coins of denomination Re 1, Rs 2 and Rs 5. The number of Rs 2 coins is 3 times the number of Rs 5 coins. The total number of coins is 160. How many coins of each denomination are with me?
What should be added to twice the rational number `(-7)/3 "to get" 3/7`?
Bansi has 3 times as many two-rupee coins as he has five-rupee coins. If he has in all a sum of Rs. 77, how many coins of each denomination does he have?
The sum of three consecutive multiples of 7 is 357. Find the smallest multiple.
Three consecutive numbers whose sum is 12 are ______, ______ and ______.
Shikha’s present age is p years. Reemu’s present age is 4 times the present age of Shikha. After 5 years Reemu’s age will be 15p years.
Sum of the ages of Anju and her mother is 65 years. If Anju’s present age is y years then her mother’s age before 5 years is (60 – y) years.
If the sum of two consecutive numbers is 93 and one of them is x, then the other number is 93 – x.
The perimeter of a rectangle is 240 cm. If its length is increased by 10% and its breadth is decreased by 20%, we get the same perimeter. Find the length and breadth of the rectangle.
