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An element with molar mass 27 g/mol forms a cubic unit cell with edge length of 405 p.m. If the density of the element is 2.7 g/cm3, what is the nature of the cubic unit cell?

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प्रश्न

An element with molar mass 27 g/mol forms a cubic unit cell with edge length of 405 p.m. If the density of the element is 2.7 g/cm3, what is the nature of the cubic unit cell?

संख्यात्मक
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उत्तर

Given:

Edge length (a) = 405 pm = 4.05 × 10−8 cm

Molar mass = 27 g mol1

Density (ρ) = 2.7 g/cm3 = 2.7 g cm3

To find: Nature of cubic unit cell

Formula: Density (ρ) = `(M n)/(a^3 N_A)`

Calculation: From the formula,

Density, ρ = `(M n)/(a^3 N_A)`

∴ `2.7 "g cm"^-3 = (27  "g mol"^-1 xx "n")/((4.05 xx 10^-8)^3 "cm"^3  xx  6.022  xx  10^23  "atom mol"^-1)`

∴ n = `(2.7 "g cm"^-3 xx (4.05 xx 10^-8)^3 "cm"^3 xx 6.022 xx 10^23  "atom mol"^-1)/(27  "g mol"^-1)`

= 4.00

∴ Number of atoms in unit cell = 4

Since the unit cell contains 4 atoms, it has a face-centred cubic (fcc) or ccp structure.

The nature of the given cubic unit cell is face-centred cubic (fcc) or ccp unit cell.

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Cubic System
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अध्याय 1: Solid State - Exercises [पृष्ठ २७]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
अध्याय 1 Solid State
Exercises | Q 9 | पृष्ठ २७

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