हिंदी

An electric heater with a power of 900 W has a resistance of 36 Ω. Calculate the magnitude of the current and the p.d. at its ends.

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प्रश्न

An electric heater with a power of 900 W has a resistance of 36 Ω. Calculate the magnitude of the current and the p.d. at its ends.

संख्यात्मक
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उत्तर

P = 900 W; R = 36 Ω; I = ?; V = ?

\[I = \sqrt{\frac{P}{R}}\]

\[= \sqrt{\frac{900}{36}}\]

\[= \sqrt{25}\]

= 5.0 A

V = I × R

= 5.0 × 36

= 180 V

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अध्याय 8: Electric Energy, Power and Household Circuits - NUMERICAL PROBLEMS ON ELECTRIC ENERGY [पृष्ठ १८०]

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics [English] Class 10
अध्याय 8 Electric Energy, Power and Household Circuits
NUMERICAL PROBLEMS ON ELECTRIC ENERGY | Q 2. | पृष्ठ १८०
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