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An Electric Bulb is Rated 240v-60w and is Working at 100% Efficiency. - Physics

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प्रश्न

An electric bulb is rated 240V-60W and is working at 100% efficiency.
(i) Calculate the resistance of bulb.
(ii) (a) Draw the circuit diagram.
(b) What is the rate of conversion of energy in each bulb?
(c) Total power used by the bulbs.

संक्षेप में उत्तर
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उत्तर

(i) From P = `"V"^2/"R"`

Resistance of bulb (R) = `"V"^2/"P" = (240 xx 240)/60 = 960 Omega`

(ii) (a)

(b) Resistance of bulbs in series = (960 + 960) Ω = 1920 Ω

∴ Current in series circuit I = `"V"/"R" = 240/1920 = 0.125` A

∴ Rate of conversion of energy in any one bulb in 1 second = I2Rt

= (0.125)2 × 960 × 1 = 15.5

(c) Power of 1 bulb in series circuit = 15 W

So poewr of 2 bulb in series circuit = 2 × 15 W = 30 W.

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अध्याय 8: Electric Power and House hold Circuits - Figure Based Long Answers

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आईसीएसई Physics [English] Class 10
अध्याय 8 Electric Power and House hold Circuits
Figure Based Long Answers | Q 5

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