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A woman starts from her home at 9.00 am, walks with a speed of 5 km h–1 on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm - Physics

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प्रश्न

A woman starts from her home at 9.00 am, walks with a speed of 5 km h–1 on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns home by an auto with a speed of 25 km h–1. Choose suitable scales and plot the x-t graph of her motion.

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उत्तर

Time at which she leaves home for the office = 9 am.

Speed of the woman = 5 km h–1

Distance between her office and home = 2.5 km

Therefore, time taken to reach the office,

`"Time taken" = "Distance"/"Speed"`

=2.5/5 = 0.5 h = 30 min
Thus, the time she reaches at her office = 9.30 a.m.

It is given that she covers the same distance in the evening by an auto.

Time at which she leaves her office = 5 pm

Now, speed of the auto = 25 km/h

`"Time taken" = "Distance"/"Speed"`

=2.5/25 = 1/10 = 0.1 h  = 6 min

Therefore, the time at which she reaches her home = 5.06 pm.

The suitable x-t graph of the motion of the woman is shown in the given figure.

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अध्याय 2: Motion in a Straight Line - Exercise [पृष्ठ २४]

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एनसीईआरटी Physics [English] Class 11
अध्याय 2 Motion in a Straight Line
Exercise | Q 2.3 | पृष्ठ २४
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