Advertisements
Advertisements
प्रश्न
A swimming pool is 200 m by 50 m and has an average depth of 2 m. By the end of a summer day, the water level drops by 2 cm. How many cubic metres of water is lost on the day?
Advertisements
उत्तर
Dimensions of swimming pool are 200 m × 50 m.
Average depth of the swimming pool = 2 m
At the end of summer day the water level drops by 2 cm.
∴ Volume of water in swimming pool = Length × Breadth × Depth
= 200 × 50 × 2
= 20000 m3
If water level drops by 2 cm, it means new level of water
= `(2 - 2/100)m` ...`[∵ 1 cm = 1/100 m]`
= 1.98 m
Volume of water after summer day = 200 × 50 × 1.98
= 19800 m3
So, water in cubic metres was lost on that day
= Initial volume – Volume after summer day
= 20000 – 19800
= 200 m3
APPEARS IN
संबंधित प्रश्न
A cuboidal water tank is 6 m long, 5 m wide and 4.5 m deep. How many litres of water can it hold? (1 m3 = 1000l)
A village, having a population of 4000, requires 150 litres of water per head per day. It has a tank measuring 20 m × 15 m × 6 m. For how many days will the water of this tank last?
If V is the volume of a cuboid of dimensions a, b, c and S is its surface area, then prove that
`1/V=2/S(1/a+1/b+1)`
The areas of three adjacent faces of a cuboid are x, y and z. If the volume is V, prove that
`V^2` = `xyz`
If the area of three adjacent faces of a cuboid are 8 `cm^2`, 18 `cm^3` and 25 `cm^3`. Find the
volume of the cuboid.
The breadth of a room is twice its height, one half of its length and the volume of the room is 512cu. m. Find its dimensions.
Half cubic meter of gold-sheet is extended by hammering so as to cover an area of 1 hectare. Find the thickness of the gold-sheet.
A godown measures 40m × 25 m × 10 m. Find the maximum number of wooden crates each measuring 1.5 m
× 1.25 m × 0.5 m that can be stored in the godown.
The surface area of the three coterminus faces of a cuboid are 6, 15 and 10 cm2 respectively. The volume of the cuboid is ______.
