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A straight conductor lies along x-axis. It carries a current of 10 A along +x direction. The magnetic field vec B due to 1 cm segment of this conductor. centred at the origin, at a point (0, 1 m, 0) - Physics

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प्रश्न

A straight conductor lies along x-axis. It carries a current of 10 A along +x direction. The magnetic field `vec B` due to 1 cm segment of this conductor. centred at the origin, at a point (0, 1 m, 0) is ______.

विकल्प

  • `(1 nT) hat j`

  • `(10 nT) hat k`

  • `-(10 nT) hat k`

  • `-(1 nT) hat j`

MCQ
रिक्त स्थान भरें
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उत्तर

A straight conductor lies along x-axis. It carries a current of 10 A along +x direction. The magnetic field `vec B` due to 1 cm segment of this conductor. centred at the origin, at a point (0, 1 m, 0) is `bbunderline((10 nT) hat k)`.

Explanation:

Given: I = 10 A

dl = 1 × 10−2 m

sin θ = 1

θ = 90°

r = 1 m

B = `(mu_0 I dl sin theta)/(4 pi x^2)`

= (4 pi xx 10^-7 xx 10 xx 10^-2 (1))/(4 pi (1)^2)`

= 10 × 10−9 T

`vec B = 10 n T hat k`

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