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A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev./min in a horizontal plane. What is the

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प्रश्न

A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev/min in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N?

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उत्तर

Mass of the stone, m = 0.25 kg

Radius of the circle, r = 1.5 m

Number of revolution per second, `n = 40/60  = 2/3` rps

Angular velocity , `omega= v/r = 2pin`

The centripetal force for the stone is provided by the tension T, in the string, i.e.,

`T = F_"Centripetal"`

= `(mv^2)/r = mromega^2 = mr(2pin)^2`

`= 0.25 xx 1.5 xx (2xx3.14xx2/3)^2`

= 6.57 N

Maximum tension in the string, Tmax = 200 N

`T_"max"` = `(mv_"  max"^2)/m`

`:.v_"max" = sqrt((T_max xx r)/m)`

` = sqrt((200xx1.5)/0.25)`

= `sqrt(1200)` = 34.64 m/s

Therefore, the maximum speed of the stone is  34 .64 m/s

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अध्याय 4: Laws of Motion - EXERCISES [पृष्ठ ७०]

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एनसीईआरटी Physics [English] Class 11
अध्याय 4 Laws of Motion
EXERCISES | Q 4.21 | पृष्ठ ७०

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