हिंदी

A Sample Space Consists of 9 Elementary Events E1, E2, E3, ..., E9 Whose Probabilities Are(I) Compute P(A), P(B) and P(A ∩ B). - Mathematics

Advertisements
Advertisements

प्रश्न

A sample space consists of 9 elementary events E1E2E3, ..., E9 whose probabilities are
P(E1) = P(E2) = 0.08, P(E3) = P(E4) = P(E5) = 0.1, P(E6) = P(E7) = 0.2, P(E8) = P(E9) = 0.07
Suppose A = {E1E5E8}, B = {E2E5E8, E9}   

 Compute P(A)P(B) and P(A ∩ B).

Advertisements

उत्तर

Let S be the sample space of the elementary events.
S = {E1E2E3, ..., E9}
Given:
A = {E1E5E8}
B = {E2E5E8, E9}
P(E1) = P(E2) = 0.08, P(E3) = P(E4) = P(E5) = 0.1, P(E6) = P(E7) = 0.2, P(E8) = P(E9) = 0.07

P(A) = P(E1) + P(E5) + P(E8) = 0.08 + 0.1 + 0.07 = 0.25  

P(B) = P(E2) + P(E5) + P(E8) + P(E9) = 0.08 + 0.1 + 0.07 + 0.07 = 0.32

Now, A ∩ B = {E5E8}

∴ P(A ∩ B) = P(E5) + P(E8) = 0.1 + 0.07 = 0.17

shaalaa.com

Notes

The solution of the problem is provided by taking P(E5) = 0.1. This information is missing in the question as given in the book.

  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 33: Probability - Exercise 33.4 [पृष्ठ ६९]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
अध्याय 33 Probability
Exercise 33.4 | Q 28.1 | पृष्ठ ६९
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×