Advertisements
Advertisements
प्रश्न
A room is 22m long, 15m broad and 6m high. Find the area of its four walls and the cost of painting including doors and windows at the rate of Rs.12per m2.
Advertisements
उत्तर
Given that:
Length (l) of room = 22m
Breadth (b) of room = 15m &
Height (h) of room = 6m
L.S.A of room
= 2 x h x (l + b)
= 2 x 6 x (22 + 15)
= 2 x 6 x 37
= 444m2
∴ Area of its 4 walls = 44m2
Cost of painting the walls = 12per m2
i.e., for 1m2 = Rs.12
∴ For 444m2
= Rs.12 x 444
= Rs.5328.
APPEARS IN
संबंधित प्रश्न
The floor of a rectangular hall has a perimeter 250 m. If the cost of panting the four walls at the rate of Rs.10 per m2 is Rs.15000, find the height of the hall.
[Hint: Area of the four walls = Lateral surface area.]
The weight of a metal block of size 5 cm by 4 cm by 3 cm is 1 kg. Find the weight of a block of the same metal of size 15 cm by 8 cm by 3 cm.
Find the surface area of a cuboid whoselength = 3.2 m, breadth = 30 dm, height = 250 cm.
If V is the volume of a cuboid of dimensions a, b, c and S is its surface area, then prove that \[\frac{1}{V} = \frac{2}{S}\left( \frac{1}{a} + \frac{1}{b} + \frac{1}{c} \right)\]
A cuboid has total surface area of 372 cm2 and its lateral surface area is 180 cm2, find the area of its base.
If each edge of a cube, of volume V, is doubled, then the volume of the new cube is
Total surface area of a box of cuboid shape is 500 sq. unit. Its breadth and height is 6 unit and 5 unit respectively. What is the length of that box ?
The length, breadth, and height of a rectangular solid are in the ratio 6 : 4 :3. If the total surface area is 1728 cm2. Find its dimensions.
375 persons can be accommodated in a room whose dimensions are in the ratio of 6 : 4 : 1. Calculate the area of the four walls of the room if the each person consumes 64m3 of air.
Two cuboids with equal volumes will always have equal surface areas.
