Advertisements
Advertisements
प्रश्न
A rectangular frame is to be suspended symmetrically by two strings of equal length on two supports (Figure). It can be done in one of the following three ways;
| (a) | ![]() |
| (b) | ![]() |
| (c) | ![]() |
The tension in the strings will be ______.
विकल्प
the same in all cases.
least in (a).
least in (b).
least in (c).
Advertisements
उत्तर
The tension in the strings will be least in (b).
Explanation:
Consider the FBD diagram of the rectangular frame

Balancing vertical forces 2T sin θ – mg = 0 ......[T is tension in the string]
⇒ 2T sin θ = mg ......(i)
Total horizontal force = T cos θ – T cos θ = 0
Now from equation (i), T = `(mg)/(2 sin θ)`
As mg is constant
⇒ `T ∝ 1/sin θ`
⇒ `T_(max) = (mg)/(2 sin θ_(min))`
`sin θ_(min)` = 0
⇒ `θ_(min)` = 0
No option matches with θ = 0°
`T_(min) = (mg)/(2 sin θ_(max))` ......(since, sin θmax = 1)
sin θmax = 1
⇒ θ = 90°
Matches with option (b)
Hence, tension is least for case (b).
APPEARS IN
संबंधित प्रश्न
Determine the volume contraction of a solid copper cube, 10 cm on an edge, when subjected to a hydraulic pressure of 7.0 ×106 Pa.
A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10–2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.
When a block a mass M is suspended by a long wire of length L, the elastic potential potential energy stored in the wire is `1/2` × stress × strain × volume. Show that it is equal to `1/2` Mgl, where l is the extension. The loss in gravitational potential energy of the mass earth system is Mgl. Where does the remaining `1/2` Mgl energy go ?
When some wax is rubbed on a cloth, it becomes waterproof. Explain.
A rope 1 cm in diameter breaks if the tension in it exceeds 500 N. The maximum tension that may be given to a similar rope of diameter 2 cm is
The breaking stress of a wire depends on
A heave uniform rod is hanging vertically form a fixed support. It is stretched by its won weight. The diameter of the rod is
Answer in one sentence.
Define strain.
A spiral spring is stretched by a weight. The strain will be:
A rod has a radius of 100 mm and a length of 10 cm. A 100 N force compress along its length. Calculate the longitudinal stress developed in the rod.
Modulus of rigidity of ideal liquids is ______.
A mild steel wire of length 2L and cross-sectional area A is stretched, well within elastic limit, horizontally between two pillars (Figure). A mass m is suspended from the mid point of the wire. Strain in the wire is ______.

A rod of length l and negligible mass is suspended at its two ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths (Figure). The cross-sectional areas of wires A and B are 1.0 mm2 and 2.0 mm2, respectively.
(YAl = 70 × 109 Nm−2 and Ysteel = 200 × 109 Nm–2)

- Mass m should be suspended close to wire A to have equal stresses in both the wires.
- Mass m should be suspended close to B to have equal stresses in both the wires.
- Mass m should be suspended at the middle of the wires to have equal stresses in both the wires.
- Mass m should be suspended close to wire A to have equal strain in both wires.
Is stress a vector quantity?
The value of tension in a long thin metal wire has been changed from T1 to T2. The lengths of the metal wire at two different values of tension T1 and T2 are l1 and l2 respectively. The actual length of the metal wire is ______.
A body of mass m = 10 kg is attached to one end of a wire of length 0.3 m. The maximum angular speed (in rad s-1) with which it can be rotated about its other end in the space station is (Breaking stress of wire = 4.8 × 107 Nm-2 and the area of cross-section of the wire = 10-2 cm2) is ______.
What is the physical quantity defined as the internal restoring force per unit area of a body?
The SI unit of stress is:



