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A particle moves along a straight line in such a way that after t seconds its distance from the origin is s = 2t2 + 3t metres. Find the average velocity between t = 3 and t = 6 seconds

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प्रश्न

A particle moves along a straight line in such a way that after t seconds its distance from the origin is s = 2t2 + 3t metres. Find the average velocity between t = 3 and t = 6 seconds

योग
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उत्तर

s = 2t2 + 3t

Average velocity between t = 3 and t = 6 seconds

Now s(t) = 2t² + 3t

Average velocity = `("s"(6) - "s"(3))/(6 - 3)`

= `([2(6^2) + 3(6)] - [2(3^2) + 3(3)])/3`

= `((72 + 18) - (18 + 9))/3`

= `(90 - 27)/3`

= `63/3`

= 21 m/s 

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Applications of Differential Calculus - Exercise 7.1 [पृष्ठ ८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 7 Applications of Differential Calculus
Exercise 7.1 | Q 1. (i) | पृष्ठ ८

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