Advertisements
Advertisements
प्रश्न
A number is as much greater than 27 as it is less than 73. Find the number.
Advertisements
उत्तर
Let the number be x.
If we subtract 27 from x i.e. (x – 27) and subtract x from 73 i.e. (73 – x), we get the same result.
Therefore, we get the following equation
x – 27 = 73 – x
⇒ x + x = 73 + 27 ...[Transposing (– 27) to RHS and (–x) to LHS]
⇒ 2x = 100
⇒ `(2x)/2 = 100/2` ...[Dividing both sides by 2]
⇒ x = 50
Hence, the required number is 50.
APPEARS IN
संबंधित प्रश्न
Solve the following equations.
`a/5 + 3 = 2`
Solve the following equations.
`q/4 + 7 = 5`
Solve the following equations
6z + 10 = -2
Sum of two numbers is 81. One is twice the other.
- If smaller number is x, the other number is ______.
- The equation formed is ______.
- The solution of the equation is ______.
- The numbers are ______ and ______.
If z + 3 = 5, then z = ______.
If 3 – x = –4, then x = ______.
If a number is increased by 20, it becomes 45. Then the number is ______.
If 4x – 7 = 11, then x = 4.
Match each of the entries in Column I with the appropriate entries in Column II.
| Column I | Column II |
| (i) x + 5 = 9 | (A) `- 5/3` |
| (ii) x – 7 = 4 | (B) `5/3` |
| (iii) `x/12 = -5` | (C) 4 |
| (iv) 5x = 30 | (D) 6 |
| (v) The value of y which satisfies 3y = 5 | (E) 11 |
| (vi) If p = 2, then the value of `1/3 (1 - 3p)` | (F) – 60 |
| (G) 3 |
Seven times a number is 12 less than thirteen times the same number. Find the number.
