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A motor car is going due north at a speed of 50 km/h. It makes a 90° left turn without changing the speed. The change in the velocity of the car is about ______. - Physics

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प्रश्न

A motor car is going due north at a speed of 50 km/h. It makes a 90° left turn without changing the speed. The change in the velocity of the car is about ______.

विकल्प

  • 50 km/h towards west

  • 70 km/h towards south-west

  •  70 km/h towards north-west

  • zero

MCQ
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उत्तर

A motor car is going due north at a speed of 50 km/h. It makes a 90° left turn without changing the speed. The change in the velocity of the car is about 70 km/h towards south-west.

Explanation:

Final velocity, \[\vec{V_f} = - 50 \hat{ i }  \text{ km } /\text{ h } \] Initial velocity, \[\vec{V_f} = - 50 \hat{ i }  \text{ km } /\text{ h } \] Change in velocity, \[∆ \vec{V} = \vec{V_f} - \vec{V_i}\] \[\left| ∆ V \right| = \sqrt{{50}^2 + {50}^2 + 2 \times 50 \times 50\cos\left( 90° \right)} = 70 \text{ km } /h\]

It is towards the southwest, as shown in the figure.

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अध्याय 3: Rest and Motion: Kinematics - MCQ [पृष्ठ ४९]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 3 Rest and Motion: Kinematics
MCQ | Q 1 | पृष्ठ ४९
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