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प्रश्न
A metre scale of weight 50 gf can be balanced at 40 cm mark without any weight suspended on it.
- If this ruler is cut at its centre then state which part [0 to 50 cm or 50 to 100 cm] of the ruler will weigh more than 25 gf.

- What minimum weight placed on this metre ruler can balance this ruler when it is pivoted at its centre?
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उत्तर
a. Cut at the centre (50 cm). Since the C.G. is at 40 cm, the 0–50 cm half contains more mass than the 50–100 cm half.
0–50 cm half weighs > 25 gf (the 50–100 cm half weighs < 25 gf).
b. By principle of moments
50 × 10 = w × 50
w = 10 gf
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संबंधित प्रश्न
Draw a diagram of a block and tackle system of pulleys having a velocity ratio of 5. In your diagram indicate clearly the points of application and the directions of the load L and effort E. Also mark the tension T in each strand.
The velocity ratio of a single movable pulley is always 2.
The velocity ratio of a combination of n movable pulleys with a fixed pulley is always 2n.
The velocity ratio of a block and tackle system is always equal to the number of strands of the tackle supporting the load.
Copy and complete the labelled diagram connecting the two pulleys with a tackle to obtain Velocity Ratio= 2.

If Load = 48 kgf and efficiency is 80% then calculate:
- Mechanical Advantage.
- Effort needed to lift the load.

The adjacent diagram shows the movable block of a block and tackle system with effort in a convenient direction. From the diagram we can conclude that the number of pulleys used in the fixed block are ______.

In a block and tackle system, increase in the weight of the movable block ______ the efficiency of the pulley system.
