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A merchant borrows ₹ 1000 and agrees to repay its interest ₹ 140 with principal in 12 monthly instalments. Each instalment being less than the preceding one by ₹ 10. Find the amount of the first

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प्रश्न

A merchant borrows ₹ 1000 and agrees to repay its interest ₹ 140 with principal in 12 monthly instalments. Each instalment being less than the preceding one by ₹ 10. Find the amount of the first instalment.

योग
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उत्तर

The installments are in A.P.

Amount repaid in 12 instalments (S12)

= Amount borrowed + Total interest

= 1000 + 140

∴ S12 = 1140

Number of instalments (n) = 12

Each instalment is less than the preceding one by ₹ 10.

∴ d = –10

Now, `S_n = n/2 [2a + (n - 1)d]`

∴ `S_12 = 12/2 [2a + (12 - 1)(-10)]`

∴ 1140 = 6[2a + 11(– 10)]

∴ 1140 = 6(2a – 110)

∴ `1140/6` = 2a – 110

∴ 190 = 2a – 110

∴ 2a = 300

∴ a = `300/2`

∴ a = 150

∴ The amount of first instalment is ₹ 150.

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