हिंदी

A medicine capsule is in the shape of cylinder with two hemispheres stuck to each of its ends (see the given figure). The length of the entire capsule is 14 mm

Advertisements
Advertisements

प्रश्न

A medicine capsule is in the shape of cylinder with two hemispheres stuck to each of its ends (see the given figure). The length of the entire capsule is 14 mm and the diameter of the capsule is 5 mm. Find its surface area. [Use π = `22/7`]

 

योग
Advertisements

उत्तर

It can be observed that

Radius (r) of cylindrical part = Radius (r) of hemispherical part 

= `"Diameter of the capsule"/2`

= `5/2`

= 2.5 mm

Length of cylindrical part (h) = Length of the entire capsule − 2 × r

= 14 − 2 × 2.5

= 9 mm

Surface area of capsule = 2 × CSA of hemispherical part + CSA of cylindrical part

= 2 × 2πr2 + 2πrh

`= 4pi(5/2)^2 + 2pi(5/2)(9)`

= 25π + 45π

= 70π mm2

= `70 xx 22/7`

= 220 mm2

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 17: Volumes and Surface Areas of Solids - EXERCISE 17A [पृष्ठ ७८८]

APPEARS IN

आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 17 Volumes and Surface Areas of Solids
EXERCISE 17A | Q 19. | पृष्ठ ७८८
एनसीईआरटी Mathematics [English] Class 10
अध्याय 12 Surface Areas and Volumes
EXERCISE 12.1 | Q 6. | पृष्ठ १६६

वीडियो ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्न

Water in a canal, 6 m wide and 1.5 m deep, is flowing at a speed of 4 km/h. How much area will it irrigate in 10 minutes, if 8 cm of standing water is needed for irrigation?


In Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD|| BC, ∠ DAB = 900, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. [Take π=22/7]

 


In Fig. 4, from the top of a solid cone of height 12 cm and base radius 6 cm, a cone of height 4 cm is removed by a plane parallel to the base. Find the total surface area of the remaining solid. (Use `pi=22/7` and `sqrt5=2.236`)


In Fig. 5, from a cuboidal solid metallic block, of dimensions 15cm ✕ 10cm ✕ 5cm, a cylindrical hole of diameter 7 cm is drilled out. Find the surface area of the remaining block [Use

`pi=22/7`]


A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m2.

(Note that the base of the tent will not be covered with canvas.) [Use `pi = 22/7`]


From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm2 

[use `pi = 22/7`]


A toy is in the form of a cone surmounted on a hemisphere. The diameter of the base and the height of cone are 6cm and 4cm. determine surface area of toy?


A bucket made of aluminum sheet is of height 20cm and its upper and lower ends are of radius 25cm an 10cm, find cost of making bucket if the aluminum sheet costs Rs 70 per
100 cm2


A cylindrical bucket 28 cm in diameter and 72 cm high is full of water. The water is emptied into a rectangular tank 66 cm long and 28 cm wide. Find the height of the water level in the tank.


A solid is composed of a cylinder with hemispherical ends. If the length of the whole solid is 108 cm and the diameter of the cylinder is 36 cm, find the cost of polishing the surface at the rate of 7 paise per cm2 .


Two cubes each of volume 27 cm3 are joined end to end to form a solid. Find the surface area of the resulting cuboid.


A toy is in the form of a cylinder with hemispherical ends. If the whole length of the toy is 90 cm and its diameter is 42 cm, find the cost of painting the toy at the rate of 70 paise per sq cm.


From a solid cylinder of height 2.8 cm and diameter 4.2 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid.


A toy is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The radius and height of the cylindrical part are 5 cm and 13 cm, respectively. The radii of the hemispherical and the conical parts are the same as that of the cylindrical part. Find the surface area of the toy, if the total height of the toy is 30 cm.


A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii of two of these balls are 1.5 cm and 2 cm. Find the radius of the third ball.


A cone of height 24 cm and radius of base 6 cm is made up of modelling clay. A child reshapes it in the form of a sphere. Find the radius of the sphere and hence find the surface area of this sphere.


The radius of spherical balloon increases from 8 cm to 12 cm. The ratio of the surface areas of balloon in two cases is ______.


The curved surface area of glass having radii 3 cm and 4 cm respectively and slant height 10 cm is ______.


There are two identical solid cubical boxes of side 7 cm. From the top face of the first cube a hemisphere of diameter equal to the side of the cube is scooped out. This hemisphere is inverted and placed on the top of the second cube’s surface to form a dome. Find

  1. the ratio of the total surface area of the two new solids formed
  2. volume of each new solid formed.

The ratio of total surface area of a solid hemisphere to the square of its radius is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×