Advertisements
Advertisements
प्रश्न
A man is standing between two vertical walls 680 m apart. He claps his hands and hears two distinct echoes after 0.9 seconds and 1.1 seconds respectively. What is the speed of sound in the air?
Advertisements
उत्तर
Given data is
d = 680 m
t1 = 0.9 s
t2 = 1.1 s
v = ?
Velocity = `"Distance travelled by sound"/"Time taken"`
V= `(2"d")/t`
d1 = `("vt"_1)/2` & d2 = `("vt"_2)/2`
d = `"v"/2` (t1 + t2)
V = `(2"d")/(("t"_1 + "t"_2))`
= `(2xx680)/((0.9 + 1.1))`
= `(2xx680)/2`
V= 680 ms-1
APPEARS IN
संबंधित प्रश्न
Which of the following statement best describes frequency?
Name three devices which work on the reflection of sound.
Fill in the blank with suitable word :
An echo is simply a ................... sound.
Fill in the blank with suitable word :
Echoes are caused by the ...................... of sound.
What is meant by 'reflection of sound' ? What type of surfaces are the best for reflecting sound ?
A man is kidnapped, blindfolded and imprisoned in a big room. How could the man tell if he was in : a furnished room
Answer the following question in your own words.
What should be the dimensions and the shape of classrooms so that no echo can be produced there?
State two conditions necessary for hearing an echo.
What is an echo? Write the conditions to hear an echo.
Rohan conducted experiments on echo in different media. He observed that a minimum distance of 'x' meters is required for the echo to be heard in oxygen and 'y' meters in benzene. Compare 'x' and 'y'. Justify your answer.
Speed of sound in oxygen: 340 ms-1
Speed of sound in benzene: 200 ms-1
