Advertisements
Advertisements
प्रश्न
A man is standing between two vertical walls 680 m apart. He claps his hands and hears two distinct echoes after 0.9 seconds and 1.1 seconds respectively. What is the speed of sound in the air?
Advertisements
उत्तर
Given data is
d = 680 m
t1 = 0.9 s
t2 = 1.1 s
v = ?
Velocity = `"Distance travelled by sound"/"Time taken"`
V= `(2"d")/t`
d1 = `("vt"_1)/2` & d2 = `("vt"_2)/2`
d = `"v"/2` (t1 + t2)
V = `(2"d")/(("t"_1 + "t"_2))`
= `(2xx680)/((0.9 + 1.1))`
= `(2xx680)/2`
V= 680 ms-1
APPEARS IN
संबंधित प्रश्न
Name three devices which work on the reflection of sound.
Name the device which is used to address a small gathering of people.
In which medium, air or water, an echo is heard much sooner ? Why ?
A man is kidnapped, blindfolded and imprisoned in a big room. How could the man tell if he was in : a bare room
Explain by giving a scientific reason.
We cannot hear the echo produced in a classroom.
Answer the following question in your own words.
What is an echo?
What are the medical applications of echo?
Assertion: The sound which we hear again is called Echo.
Reason: The sensation of sound (Echo) persists in our brain for about 1 s.
Answer the following question in your own words.
What factors are important to get a distinct echo?
Rohan conducted experiments on echo in different media. He observed that a minimum distance of 'x' meters is required for the echo to be heard in oxygen and 'y' meters in benzene. Compare 'x' and 'y'. Justify your answer.
Speed of sound in oxygen: 340 ms-1
Speed of sound in benzene: 200 ms-1
