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A line is drawn perpendicular to 5x = y + 7. Find the equation of the line if the area of the triangle formed by this line with co-ordinate axes is 10 sq.units

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प्रश्न

A line is drawn perpendicular to 5x = y + 7. Find the equation of the line if the area of the triangle formed by this line with co-ordinate axes is 10 sq.units

योग
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उत्तर


Let the given line be PQ whose equation is

5x = y + 7

5x – y – 7 = 0   ......(1)

Let AB be the line perpendicular to the line PQ such that the area of the triangle OAB is 10 units.

The equation of the line AB is

– x – 5y + k = 0

x + 5y – k = 0

x + 5y = k   ......(2)

`x/"l" + (5y)/"k"` = 1

`x/"k" + y/("k"/5)` = 1

∴ A is (k, 0) and B is `(0, "k"/5)`

OA = k and OB = `"k"/5`

Area of ∆OAB = `1/2 xx "OA" xx "OB"`

= `1/2 xx "k" xx "k"/5`

Given area of ∆OAB = 10

∴ `("k"^2)/10` = 10

k2 = 100

⇒ k = ±10

∴ The required equation of the straight line is

x + 5y = ±10

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Angle Between Two Straight Lines
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Two Dimensional Analytical Geometry - Exercise 6.3 [पृष्ठ २७२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Two Dimensional Analytical Geometry
Exercise 6.3 | Q 16 | पृष्ठ २७२

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