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Find the distance between the parallel lines3x − 4y + 5 = 0 and 6x − 8y − 15 = 0

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प्रश्न

Find the distance between the parallel lines
3x − 4y + 5 = 0 and 6x − 8y − 15 = 0

योग
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उत्तर

3x – 4y + 5 = 0 and 6x – 8y – 15 = 0

The equation of the given lines are

3x – 4y + 5 = 0   ......(1)

6x – 8y – 15 = 0

3x – 4y – 1 = 0    ......(2)

The distance between the parallel lines (1) and (2) is

d = `(5 - ( - 15/2))/sqrt(3^2 + (- 4)^2`

= `(5 + 15/2)/sqrt(9 + 16)`

= `(10 + 15)/(2sqrt(25))`

= `25/(2 xx 5)`

= `5/2`

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Angle Between Two Straight Lines
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Two Dimensional Analytical Geometry - Exercise 6.3 [पृष्ठ २७२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Two Dimensional Analytical Geometry
Exercise 6.3 | Q 12. (ii) | पृष्ठ २७२

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