Advertisements
Advertisements
प्रश्न
A line cutting off intercept – 3 from the y-axis and the tangent at angle to the x-axis is `3/5`, its equation is ______.
विकल्प
5y – 3x + 15 = 0
3y – 5x + 15 = 0
5y – 3x – 15 = 0
None of these
MCQ
रिक्त स्थान भरें
Advertisements
उत्तर
A line cutting off intercept – 3 from the y-axis and the tangent at angle to the x-axis is `3/5`, its equation is 5y – 3x + 15 = 0.
Explanation:
Since the lines cut off intercepts – 3 on y-axis then the line is passing through the point (0, – 3).
Given that: tan θ = `3/5`
⇒ Slope of the line m = `3/5`
So, the equation of the line is y – y1 = m(x – x1)
⇒ y + 3 = `3/5(x - 0)`
⇒ 5y + 15 = 3x
⇒ 3x – 5y – 15 = 0
⇒ 5y – 3x + 15 = 0
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
