Question

A lead pellet of mass 4 g leaves an air gun with a velocity of 50 ms⁻¹. What is the magnitude of potential energy stored by the spring of air gun?

Answer 1

Given mass = 4 g \[= \frac{4}{1000}\ \mathrm{kg} \]

Velocity (v) = 50 m s⁻¹

∴ Kinetic energy of pellet \[= \frac{1}{2}\, mv^{2} \]

\[= \frac{1}{2} \times \frac{4}{1000} \times 50 \times 50 \]

= 5 J

Now, potential energy = kinetic energy = 5 J