Advertisements
Advertisements
प्रश्न
A force of 50 N acts on a body and moves it a distance of 4 m on horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface.
Advertisements
उत्तर
We have a situation in which, work is done by force acting obliquely.
Force, (F) = 50 N
Distance travelled by the body, (S) = 4 m
Angle between force and direction of distance, (θ) = 60°
We have a relation as,
W = (F)(S) cos θ
So,
`W = (50) (4) cos 60^circ`
= `200 (1/2)` J
= 100 J
So , the work done is 100 J .
APPEARS IN
संबंधित प्रश्न
Write an expression for the work done when a force is acting on an object in the direction of its displacement.
In each of the following a force, F is acting on an object of mass, m. The direction of displacement is from west to east, as shown by the longer arrow. Observe the diagrams carefully and state whether the work done by the force is negative, positive or zero.
A man lifts a mass of 20 kg to a height of 2.5 m. Assuming that the force of gravity on 1 kg mass is 10 N, find the work done by the man.
A body of mass 5 kg falls from a height of 10 m to 4 m. Calculate:
The loss in potential energy of the body,
Find the kinetic energy of a body of mass 1 kg moving with a uniform velocity of 10 m s-1.
Give two examples of couple action in our daily life.
When you move upstairs, do you perform some work?
Fill in the boxe to show the corresponding energy transformation.
Can two agents, doing the same work, have different power?
