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प्रश्न
| A cuboidal wooden toy is of dimensions 14 cm × 17 cm × 4 cm. On its top, there are seven cylindrical hollows for bees to fit in. Each cylindrical hollow is of height 3 cm and radius 2 cm. |
Based on the above information, answer the following questions.
- Find the volume of the wood carved out to make one cylindrical hollow.
- Find the lateral surface area of the cuboid to paint it with green colour.
- Find the volume of wood in the remaining cuboid after carving out the seven cylindrical hollows.
- Find the surface area of the top surface of the cuboid to be painted yellow.
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उत्तर
i. Volume of wood carved out for one cylindrical hollow
Given: Radius of hollow, \[r = 2\text{ cm}\]
Height of hollow, \[h = 3\text{ cm}\]
Formula: \[V = \pi r^2 h\]
Calculation: \[V = \frac{22}{7} \times 2^2 \times 3 = \frac{264}{7} \approx 37.71\text{ cm}^3\]
ii. Lateral surface area of the cuboid
Given: Dimensions of cuboid: \[l = 14\text{ cm}\], \[b = 17\text{ cm}\], \[h_c = 4\text{ cm}\]
Formula: \[\text{LSA} = 2(l + b)h_c\]
Calculation: \[\text{LSA} = 2(14 + 17) \times 4\]
\[\text{LSA} = 2 \times 31 \times 4 = 248\text{ cm}^2\]
iii. Volume of wood in the remaining cuboid
Calculation: \[\text{Volume of cuboid} = l \times b \times h_c = 14 \times 17 \times 4 = 952\text{ cm}^3\]
\[\text{Volume of 7 hollows} = 7 \times \frac{264}{7} = 264\text{ cm}^3\]
\[\text{Remaining Volume} = 952 - 264 = 688\text{ cm}^3\]
iv. Surface area of the top surface to be painted yellow
Formula: \[\text{Area} = (l \times b) - 7 \times (\pi r^2)\]
Calculation: \[\text{Area} = (14 \times 17) - \left(7 \times \frac{22}{7} \times 2^2\right)\]
\[\text{Area} = 238 - 88 = 150\text{ cm}^2\]
