Question

A child has a die whose six faces show the letters as shown below:

\[\boxed{\text{A}}\] \[\boxed{\text{A}}\] \[\boxed{\text{B}}\] \[\boxed{\text{C}}\] \[\boxed{\text{C}}\] \[\boxed{\text{C}}\]

The die is thrown once. What is the probability of getting (i) A, (ii) C?

Answer 1

Total possible outcomes n(s) = 6

(i) Let E₁ = Getting event letter A, then n(E₁) = 2

∴ Probability = `(n(E_1))/(n(s))`

= `2/6`

= `1/3`

(ii) Let E₂ = Getting event letter C, then n(E₂) = 3

∴ Probability = `(n(E_2))/(n(s))`

= `3/6`

= `1/2`