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A box contains 5 green pencils and 7 yellow pencils. Two pencils are chosen at random from the box without replacement. What is the probability that both are yellow?

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प्रश्न

A box contains 5 green pencils and 7 yellow pencils. Two pencils are chosen at random from the box without replacement. What is the probability that both are yellow?

योग
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उत्तर

Total number of pencils = 5 + 7 = 12

Let event A : The first pencil chosen is yellow.

∴ P(A) = `(""^7"C"_1)/(""^12"C"_1) = 7/12`

Let event B : The second pencil chosen is yellow.

Since the first yellow pencil is not replaced in the box, we now have 11 pencils, out of which 6 are .

∴ Probability that the second pencil is yellow under the condition that the first yellow pencil is not replaced in the box

= `"P"("B"//"A")`

= `(""^6"C"_1)/(""^11"C"_1)`

= `6/11`

∴ Required probability = P(A ∩ B)

= `"P"("B"//"A")*"P"("A")`

= `6/11 xx 7/12`

= `7/22`.

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अध्याय 9: Probability - Exercise 9.3 [पृष्ठ २०५]

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