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A Block Weighing 10 N Travels Down a Smooth Curved Track Ab Joined to a Rough Horizontal Surface (Figure Following ). the Rough Surface Has a Friction Coefficient of 0⋅20 with the Block.

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प्रश्न

A block weighing 10 N travels down a smooth curved track AB joined to a rough horizontal surface (In the following figure). The rough surface has a friction coefficient of 0⋅20 with the block. If the block starts slipping on the track from a point 1⋅0 m above the horizontal surface, how far will it move on the rough surface?

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उत्तर

Given,

\[\text{ Weight of the block, mg = 10 N}\]

\[\text{ Friction coefficient, } \mu = 0 . 2\]

\[\text{ Initial height of the block, H = 1 m }\]

\[\text{ Initial velocity = Final velocity }= 0\]

Potential energy of the block at the top of the curved track = Kinetic energy of the block at the bottom of the track

\[\Rightarrow \text{ K . E . = mgh }= 10 \times 1 = 10 J\]

Again on the horizontal surface the frictional force,

\[\text{ F } = \mu \text{ R } = \mu \text{ mg } = 10 \times 1 = 10 J\]
So, the K.E. is used to overcome friction.
\[\Rightarrow S = \frac{W}{F} = \frac{10}{2} = 5 \text{ m }\]

The block stops after covering 5 m on the rough surface.

 
 
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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Work and Energy - Exercise [पृष्ठ १३४]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 8 Work and Energy
Exercise | Q 37 | पृष्ठ १३४

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