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A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes in a Young’s double-slit experiment. Find the distance of the third bright fringe on the screen

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प्रश्न

A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes in a Young’s double-slit experiment.

Find the distance of the third bright fringe on the screen from the central maximum for wavelength 650 nm.

संख्यात्मक
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उत्तर

Here, d = 2 mm = 2 × 10-3 m, D = l.2 m, λ1 = 650 nm = 650 × 10−9 m, λ2 = 520 nm = 520 × 10−9 m

Distance of the third bright fringe from the central maximum for the wavelength 650 nm:

y3 = `(3λ_1D)/d`

= `(3(650 xx 10^-9)1.2)/(2 xx 10^-3)`

= 1.17 × 10-3 m

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अध्याय 10: Wave Optics - EXERCISES [पृष्ठ २७३]

APPEARS IN

एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 10 Wave Optics
EXERCISES | Q 10.6 (a) | पृष्ठ २७३
एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 10 Wave Optics
Exercise | Q 10.6 (a) | पृष्ठ ३८३

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