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A battery of e.m.f 16 V and internal resistance 2 Ω is connected to two resistors 3Ω and 6Ω connected in parallel. Find: a. the current through the battery. b. p.d. between the terminals of the

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प्रश्न

A battery of e.m.f 16 V and internal resistance 2 Ω is connected to two resistors 3Ω and 6Ω connected in parallel. Find:

  1. the current through the battery.
  2. p.d. between the terminals of the battery,
  3. the current in 3 Ω resistors,
  4. the current in 6 Ω resistor. 
संख्यात्मक
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उत्तर

E.m.f. of battery E = 16V, r = 2Ω

Effective resistance of 3Ω and 6Ω connected in parallel R is

`1/"R" = 1/3 + 1/6`

= `3/6`

= `1/2`

∴ R = 2Ω

Total resistance = (R + r)

= (2 +2)

= 4Ω

(a) Current through battery
I = `"V"/("R" + r) = "E"/("R" +r)`

I = `(16V)/(4Ω)`

= 4 A

(b) p.d between terminal of battery

V = IR

= 4 × 2

= 8V

(c) The current in 3Ω resistor

I1 = `"V"/"R"`

= `8/3`

= 2.66 A

(d) The current in 6Ω resistor 

I2 = `"V"/"R"`

= `8/6`

= 1.34 A

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अध्याय 8: Current Electricity - EXERCISE - 8(B) [पृष्ठ २०३]

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सेलिना Physics [English] Class 10 ICSE
अध्याय 8 Current Electricity
EXERCISE - 8(B) | Q 27. | पृष्ठ २०३

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