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A Ball of Mass 0.50 Kg Moving at a Speed of 5.0 M/S Collides with Another Ball of Mass 1.0 Kg. After the

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प्रश्न

A ball of mass 0.50 kg moving at a speed of 5.0 m/s collides with another ball of mass 1.0 kg. After the collision the balls stick together and remain  motionless. What was the velocity of the 1.0 kg block before the collision?

योग
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उत्तर

It is given that:
Speed of the ball, v1 = 5.0 m/s 
Mass of the ball, m1 = 0.5 kg
Mass of another ball, m2 = 1 kg
Let the velocity  of this ball be v2 m/s.

On applying the law of conservation of momentum, we get:

\[m_1 v_1 + m_2 v_2 = 0\]

\[0 . 5 \times 5 + 1 \times v_2 = 0\]

\[ \Rightarrow v_2 = - 2 . 5 \text{ m/s }\]
Hence, the velocity of second ball is 2.5 m/s, opposite to the direction of motion of the first ball.

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Momentum Conservation and Centre of Mass Motion
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Centre of Mass, Linear Momentum, Collision - Exercise [पृष्ठ १६२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 9 Centre of Mass, Linear Momentum, Collision
Exercise | Q 31 | पृष्ठ १६२

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