Question

5% pupil in a town died due to some diseases and 3% of the remaining left the town. If 2, 76, 450 pupil are still in the town; find the original number of pupil in the town.

Answer 1

Let original number of pupil in the town = 100

Number of pupil died due to disease

= `(5)/(100) xx 100` = 5

Remaining pupil = 100 - 5 = 95

Number of pupil who left the town

= `(3)/(100) xx 95`

= `(3 xx 95)/(100)`

= `(57)/(20)`

Actual remaining pupil

= `95 - (57)/(20)`

= `(1900 - 57)/(20)`

= `(1843)/(20)`

If the remaining pupil in the town are `(1843)/(20)`, then original number of pupil = 100

If the remaining pupil in the town is 1, then original number of pupil = `100 xx (20)/(1843)`

If the remaining pupil in the town are 276450, the original number of pupil

= `100 xx (20)/(1843)xx 276450`

= `(100 xx 20 xx 276450)/(1843)`

= 100 × 20 × 150

= 3,00,000.