Question

`[(3/7)^-3]^4` = ______

विकल्प

• `(3/7)^-7`

• `(3/7)^-10`

• `(7/3)^12`

• `(3/7)^20`

Answer 1

`[(3/7)^-3]^4 = bbunderline((7/3)^12)`

स्पष्टीकरण:

`[(3/7)^-3]^4 = (3/7)^(-3(4))` ...[∵ (a^m)ⁿ = a^mn] 

`= (3/7)^-12`

`= (7/3)^12`     ....`[∵ (a)^-"n" = 1/"a"^"n"]`