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2x + 3y − Z = 0 X − Y − 2z = 0 3x + Y + 3z = 0

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प्रश्न

2x + 3y − z = 0
x − y − 2z = 0
3x + y + 3z = 0

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उत्तर

The given system of homogeneous equations can be written in matrix form as follows:
\[\begin{bmatrix}2 & 3 & - 1 \\ 1 & - 1 & - 2 \\ 3 & 1 & 3\end{bmatrix}\begin{bmatrix}x \\ y \\ z\end{bmatrix} = \begin{bmatrix}0 \\ 0 \\ 0\end{bmatrix}\]
AX = O
Here, 
\[ A = \begin{bmatrix}2 & 3 & - 1 \\ 1 & - 1 & - 2 \\ 3 & 1 & 3\end{bmatrix}, X = \begin{bmatrix}x \\ y \\ z\end{bmatrix}\text{ and }O = \begin{bmatrix}0 \\ 0 \\ 0\end{bmatrix}\]
Now,
\[ \left| A \right| = \begin{vmatrix}2 & 3 & - 1 \\ 1 & - 1 & - 2 \\ 3 & 1 & 3\end{vmatrix}\]
\[ = 2\left( - 3 + 2 \right) - 3\left( 3 + 6 \right) - 1\left( 1 + 3 \right)\]
\[ = - 2 - 27 - 4\]
\[ = - 33 \neq 0\]
So, the given systemof homogeneous equations has only trivial solution, which is given below:
\[x=y=z=0\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Solution of Simultaneous Linear Equations - Exercise 8.2 [पृष्ठ २१]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 7 Solution of Simultaneous Linear Equations
Exercise 8.2 | Q 8 | पृष्ठ २१

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