हिंदी
सी.आई.एस.सी.ई.आईसीएसई ICSE Class 7

2550 – 510 – {270 – (90 – Bar(80 + 7))} - Mathematics

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प्रश्न

`2550 – [510 – {270 – (90 – bar(80 + 7))}]`

योग
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उत्तर

`2550 – [510 – {270 – (90 – bar(80 + 7))}]`

= 2550 – [510 – {270 – (90 – 87)}]

= 2550 - [510 - {270 - 3}]

= 2550 - [510 - 267]

= 2550 – 243

= 2307

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Properties of Operations on Integers
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Integers - Exercise 1 (C)

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सेलिना Concise Mathematics [English] Class 7 ICSE
अध्याय 1 Integers
Exercise 1 (C) | Q 9
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