मराठी
सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

2550 – 510 – {270 – (90 – Bar(80 + 7))} - Mathematics

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प्रश्न

`2550 – [510 – {270 – (90 – bar(80 + 7))}]`

बेरीज
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उत्तर

`2550 – [510 – {270 – (90 – bar(80 + 7))}]`

= 2550 – [510 – {270 – (90 – 87)}]

= 2550 - [510 - {270 - 3}]

= 2550 - [510 - 267]

= 2550 – 243

= 2307

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Properties of Operations on Integers
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Integers - Exercise 1 (C)

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