Question

16 years ago, at the time of marriage, Ajay was 5 years elder to his wife. The present ages of the wife and Ajay are in the ratio 8 : 9. Find their ages at the time of their marriage.

Answer 1

Given:

16 years ago (at marriage) Ajay was 5 years elder to his wife.

Present ages of wife: Ajay = 8 : 9.

Step-wise calculation:

1. Let wife’s present age = 8x and Ajay’s present age = 9x.

2. Their present age difference = 9x – 8x = x.

3. Age difference is constant, so x = 5 (Ajay is 5 years older).

4. Present ages: wife = 8x = 8 × 5 = 40 years; Ajay = 9x = 9 × 5 = 45 years.

5. Ages at the time of marriage (16 years ago): Wife = 40 – 16 = 24 years; Ajay = 45 – 16 = 29 years.

At the time of their marriage: Ajay = 29 years, Wife = 24 years.