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प्रश्न
123x2y – 138x2y is a like term of ______.
विकल्प
10xy
–15xy
–15xy2
10x2y
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उत्तर
123x2y – 138x2y is a like term of `bb(underline(10x^2y))`.
Explanation:
123x2y – 138x2y = (123 – 138)x2y
= –15x2y
Therefore, –15x2y is a like term of 10x2y, because both contain x2y.
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संबंधित प्रश्न
Take away:
\[\frac{6}{5} x^2 - \frac{4}{5} x^3 + \frac{5}{6} + \frac{3}{2}x \text { from }\frac{x^3}{3} - \frac{5}{2} x^2 + \frac{3}{5}x + \frac{1}{4}\]
Take away:
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