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`(1-tan^2 Theta)/(Cot^2-1) = Tan^2 Theta` - Mathematics

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`(1-tan^2 theta)/(cot^2-1) = tan^2 theta`

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LHS = `(1- tan^2 theta)/(cot^2 theta-1)`

      =`(1-(sin^2 theta)/(cos^2 theta))/((cos^2 theta )/(sin^2 theta)-1)`

      =`((cos^2 theta - sin^2 theta)/(cos^2 theta))/((cos^2theta-sin^2 theta)/(sin^2 theta))`

     =`(sin^2 theta)/(cos^2 theta)`

     = tan2 ЁЭЬГ 
     = RHS

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рдЕрдзреНрдпрд╛рдп 8: Trigonometric Identities - Exercises 1

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рдЖрд░.рдПрд╕. рдЕрдЧреНрд░рд╡рд╛рд▓ Mathematics [English] Class 10
рдЕрдзреНрдпрд╛рдп 8 Trigonometric Identities
Exercises 1 | Q 18.2

рд╕рдВрдмрдВрдзрд┐рдд рдкреНрд░рд╢реНрди

Show that `sqrt((1+cosA)/(1-cosA)) = cosec A + cot A`


Prove that (cosec A – sin A)(sec A – cos A) sec2 A = tan A.


Without using trigonometric tables evaluate

`(sin 35^@ cos 55^@ + cos 35^@ sin 55^@)/(cosec^2 10^@ - tan^2 80^@)`


Prove the following trigonometric identities.

`1/(sec A + tan A) - 1/cos A = 1/cos A - 1/(sec A - tan A)`


Prove the following identities:

`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`


Prove that:

(1 + tan A . tan B)2 + (tan A – tan B)2 = sec2 A sec2 B


Prove that:

`1/(sinA - cosA) - 1/(sinA + cosA) = (2cosA)/(2sin^2A - 1)`


Prove that:

`cosA/(1 + sinA) = secA - tanA`


`cosec theta (1+costheta)(cosectheta - cot theta )=1`


Prove that `( sintheta - 2 sin ^3 theta ) = ( 2 cos ^3 theta - cos theta) tan theta`


If x = a sin θ and y = b cos θ, what is the value of b2x2 + a2y2?


If 5x = sec θ and \[\frac{5}{x} = \tan \theta\]find the value of \[5\left( x^2 - \frac{1}{x^2} \right)\] 


If x = a sec θ and y = b tan θ, then b2x2 − a2y2 =


Prove the following identity :

`(cosecA - sinA)(secA - cosA)(tanA + cotA) = 1`


Prove the following identity : 

`sqrt((1 + cosA)/(1 - cosA)) = cosecA + cotA`


Prove that `sqrt((1 - sin θ)/(1 + sin θ)) = sec θ - tan θ`.


Prove that `tan^3 θ/( 1 + tan^2 θ) + cot^3 θ/(1 + cot^2 θ) = sec θ. cosec θ - 2 sin θ cos θ.`


If cos 9α = sinα and 9α < 90°, then the value of tan5α is ______.


If cot θ = `40/9`, find the values of cosec θ and sinθ,

We have, 1 + cot2θ = cosec2θ

1 + `square` = cosec2θ

1 + `square` = cosec2θ

`(square + square)/square` = cosec2θ

`square/square` = cosec2θ  ......[Taking root on the both side]

cosec θ = `41/9`

and sin θ = `1/("cosec"  θ)`

sin θ = `1/square`

∴ sin θ =  `9/41`

The value is cosec θ = `41/9`, and sin θ = `9/41`


Prove that `(cot A - cos A)/(cot A + cos A) = (cos^2 A)/(1 + sin A)^2`


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