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1+sinθ1-sinθ=(secθ+tanθ) - Mathematics

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प्रश्न

`sqrt((1+sin theta)/(1-sin theta)) = (sec theta + tan theta)`

योग
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उत्तर

LHS = `sqrt((1+sin theta)/(1-sin theta))`

       =`sqrt(((1+ sin theta))/(1- sin theta) xx ((1+sin theta))/(1+ sin theta))`

      =` sqrt(((1+sin theta)^2)/(1-sin^2 theta))`

      =`sqrt(((1+ sin theta)^2)/(cos^2 theta))`

     =`(1+sin theta)/cos theta`

     =`1/cos theta+ (sin theta)/(cos theta)`

     = (sec 𝜃 + tan 𝜃)
      = RHS

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अध्याय 8: Trigonometric Identities - Exercises 1

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 8 Trigonometric Identities
Exercises 1 | Q 21.1

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